Use the cross rule to determine the ratio of quantities of the starting solution and water: 25 5 200 5 m m 25%NH water 3 = 5 20 Now determine the quantity of water required to prepare the solution: 5a20 10020 5 Ay x= 100ax =400g How many grams of a ... But the problem calls for 500 g instead of 20 g of the 10 per cent 16.

Title | : | Mole Concept For Iit-Jee |

Author | : | Shishir Mittal |

Publisher | : | Tata McGraw-Hill Education - |

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